If the time interval between the occurrence of two events is measured in a frame with no relative motion in which two events occur. Then the time measured by the observer in a frame moving with relative velocity v is _.
Correct answer: B. t = t0 / √(1-v²/c²)
- A. t = t0 * √(1-v²/c²)
- B. t = t0 / √(1-v²/c²)
- C. t = t0 * (1-v²/c²)^{3/2}
- D. t = t0 / (1-v²/c²)
Explanation
The correct answer is Option B: t = t0 / √(1-v²/c²). This formula arises from the theory of special relativity and describes time dilation, which states that time measured in a moving frame appears to be longer compared to a stationary frame. The Lorentz factor, √(1-v²/c²), accounts for the effects of relative motion on the perception of time. The other options incorrectly apply or modify this factor, resulting in incorrect calculations of time dilation.
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Classical physics cannot explain blackbody radiation and related observations, leading to Planck’s quantum theory, in which energy is emitted or absorbed in discrete packets. Photons provide the particle model of light, with energy and momentum linked to frequency and wavelength, including the photoelectric effect and its threshold frequency.
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