If the temperature of the black body doubles, the intensity of radiation from it will become:
Correct answer: D. sixteen times
- A. double
- B. four times
- C. six times
- D. sixteen times
Explanation
BLACK BODY: A blackbody is a theoretical or model body that absorbs all radiation falling on it, reflecting or transmitting none. It is a hypothetical object that is a "perfect" absorber and "perfect" emitter of radiation over all wavelengths. Stefan-Boltzmann Law: It relates the total energy emitted (E) to the absolute temperature (T). E ∝ T⁴ We know that the intensity of the radiation from a black body is directly proportional to its energy. Thus, it can be concluded that if we increase the temperature of the black body by 2 (i.e., we double it), the intensity increases by 2⁴ i.e. it increases 16 times). Thus, option 'D' is the correct answer.
This question appeared on the ETEA MDCAT 2011 paper, which you can sit online with every answer explained.
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About Quantum Theory and Radiation
Quantum theory treats electromagnetic radiation as packets of energy called photons, with energy proportional to frequency through E equals hf. The topic covers Planck's hypothesis, photon momentum, the photoelectric effect, threshold frequency, work function and wave particle duality, distinguishing quantised energy exchange from classical continuous radiation.
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