If the speed of sound is 340 m/s, the length of the shortest closed pipe that resonates at 100 Hz is:
Correct answer: D. 85 cm
- A. 170 cm
- B. 42.5 cm
- C. 17 cm
- D. 85 cm
Explanation
Closed pipe fundamental f = v/(4L) ⇒ L = v/(4f) = 340/(400) = 0.85 m = 85 cm. Thus, option D is correct.
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Progressive waves transfer energy through oscillations, with wavelength, frequency, amplitude and wave speed related by v = fλ; sound speed depends on the medium. Superposition produces interference and stationary waves in strings and organ pipes, while simple harmonic motion describes the oscillation itself and must be distinguished from wave propagation.
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