If the solubility product of AgBrO3 and Ag2SO4 are 5.5 x 10^-5 and 2 x 10^-5 respectively. The relationship between the solubilities of these can be correctly represented as
Correct answer: B. AgBrO3 < Ag2SO4
- A. AgBrO3 > Ag2SO4
- B. AgBrO3 < Ag2SO4
- C. AgBrO3 = Ag2SO4
- D. AgBrO3 << Ag2SO4
Explanation
Matches the calculation: Ag₂SO₄ has the larger solubility value (~0.017) vs AgBrO₃ (~0.007). So AgBrO₃ < Ag₂SO₄.
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