If the rate of emission of energy from a star is 2.7 x 10^36 J/sec. The rate of loss of mass in the star will be :
Correct answer: B. 3 x 10^19 kg/sec
- A. 3 x 10^18 kg/sec
- B. 3 x 10^19 kg/sec
- C. 3 x 10^20 kg/sec
- D. 3 x 10^21 kg/sec
Explanation
This is the solution:E = mc2m = E/c2= 2.7 x 1036 /9 x 1016= 27 x 1035 /9 x 1016= 3 x 1019 kg/secTherefore, it is the correct option.
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Classical physics cannot explain blackbody radiation and related observations, leading to Planck’s quantum theory, in which energy is emitted or absorbed in discrete packets. Photons provide the particle model of light, with energy and momentum linked to frequency and wavelength, including the photoelectric effect and its threshold frequency.
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