If the potential at a point which is 1m from a charge is 1 volt, then the potential at a point which is 2m from the same charge will be:
Correct answer: C. 0.5 V
- A. 2 V
- B. 1 V
- C. 0.5 V
- D. 3 V
Explanation
Electric potential is given by V= kQ/rAs V is inversely proportional to r so increasing the R by a factor of 2 (1m to 2m), the electric potential, subsequently, drops by a factor of 2 (1 V -> 0.5 V).
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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