If the plane of the rectangular coil is parallel to the magnetic field (i.e radial magnetic field) the torque on the coil is_____________________?
Correct answer: D. τ = NIAB
- A. τ = NIAB cosφ
- B. τ = NIAB sinφ
- C. τ = NIAB tanφ
- D. τ = NIAB
Explanation
The torque on a current-carrying coil is τ = NIAB sinθ, where θ is the angle between the coil's normal and the magnetic field. If the plane of the coil is parallel to the field, its normal is perpendicular to the field, so θ = 90° and τ = NIAB. The likely wrong choice is b, which gives zero only if θ is incorrectly taken as the angle between the plane and the field.
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About Magnetic Flux Density
Magnetic flux density measures the magnetic force acting on a current carrying conductor or moving charge in a magnetic field. Work includes the relations B equals F divided by IL and F equals qvB, the tesla as its SI unit, field direction and the distinction between flux density and magnetic flux.
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