If the mass of the bob of simple pendulum is doubled, its time period is:
Correct answer: C. Remains constant
- A. One half
- B. Doubled
- C. Remains constant
- D. One fourth
Explanation
c) Remains constant:This option suggests that if the mass of the bob of a simple pendulum is doubled, its time period will remain constant. This is correct. The time period of a simple pendulum is primarily determined by the length of the pendulum and the acceleration due to gravity. It is independent of the mass of the bob.
Last updated
About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
Practise Waves
1,281 free Waves MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Physics questions like this
Physics is on 13 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
1 rev min-1 is equal to:
85.95° degree in terms of radian is
A 0.3 kg mass oscillates with amplitude 0.08 m. If its maximum kinetic energy is 0.096 J, what is the angular frequency?
A 0.5 kg mass on a spring (k = 50 N/m) is damped with a damping constant b = 2 kg/s. What is the damping ratio?
A 1 kg mass oscillates with SHM of amplitude 0.05 m and frequency 2 Hz. What is the total mechanical energy?