If the magnitude of charges on two point objects is doubled and the distance between them is also doubled, then force will be: ...
Correct answer: C. Unchanged
- A. Two times
- B. Four times
- C. Unchanged
- D. Halved
Explanation
Initially, the force between charges say q1 and q2 seperated with distance r is :F=4πϵ0 1 r2q1 q2 Step 2: New force calculationWhen the charge is doubled and the distance between charges is also doubled, i.e q1′ =2q1 ,q2′ =2q2 ,r′=2r The new force will be : F′=4πϵ0 1 r′2q1′ q2′ F′=4πϵ0 1 (2r)2(2q1 )(2q2 ) =4πϵ0 1 r2q1 q2 =F Hence, the force will remain the same
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