If the length of a simple pendulum is 0.4 m and the mass of pendulum's bob is 1 kg, then the time period of the pendulum will be(Note: Take the acceleration due to gravity as 9.8 m/s2.)
Correct answer: B. 1.269 s
- A. 0.405 s
- B. 1.269 s
- C. 2.007 s
- D. 12.44 s
Explanation
The time period of a simple pendulum is determined by the formula \( T = 2\pi\sqrt{\frac{L}{g}} \), where \( L \) is the length of the pendulum and \( g \) is the acceleration due to gravity. Substituting the given values, \( L = 0.4 \) m and \( g = 9.8 \) m/s², we get \( T = 2\pi\sqrt{\frac{0.4}{9.8}} \approx 1.269 \) s. Options A, C, and D are incorrect as they do not result from the proper application of this formula.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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