If the internal energy of an ideal gas decreases by the same amount as the work done by the system, then the____________________?
Correct answer: C. Both B. and C.
- A. Process must be isobaric
- B. Temperature must decrease
- C. Both B. and C.
- D. Process must be adiabatic
Explanation
Using ΔU = Q − W, a decrease in internal energy equal to the work done by the system gives Q = 0, so the process is adiabatic. For an ideal gas, internal energy depends only on temperature, so the temperature also decreases.
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