If the initial velocity ′u′ of the projectile is doubled, height H' of the projectile becomes:
Correct answer: D. 4H
- A. H/2
- B. H/4
- C. 2H
- D. 4H
Explanation
4H Explanation: The maximum height (H) of a projectile is given by H = u²sin²(θ) / 2g, where u is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity. If u is doubled (2u), the new height (H') will be H' = (2u)²sin²(θ) / 2g = 4u²sin²(θ) / 2g = 4H.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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