If the distance between two point charges to become double then the coulumb's force will be:
Correct answer: D. F/4
- A. F/2
- B. 4F
- C. 2F
- D. F/4
Explanation
According to Coulomb's Law, the electrostatic force (F) between two point charges is inversely proportional to the square of the distance (r) between them, expressed as F ∝ 1/r2. When the distance is doubled (r' = 2r), the new force (F') is proportional to 1/(2r)2 = 1/4r2. Therefore, F' = F/4. This shows that when the distance between the charges is doubled, the force becomes one-fourth of its original value.Option A (F/2) is incorrect because it assumes a linear relationship, which does not apply here. Option B (4F) is incorrect as it suggests the force increases with distance, which is contrary to Coulomb's Law. Option C (2F) is incorrect for the same reason as Option A, misinterpreting the inverse-square law of force dependency on distance.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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