If the distance between two point charges to become double then the coulumb's force will be:
Correct answer: D. F/4
- A. F/2
- B. 4F
- C. 2F
- D. F/4
Explanation
According to Coulomb's Law, the electrostatic force (F) between two point charges is inversely proportional to the square of the distance (r) between them, expressed as F ∝ 1/r2. When the distance is doubled (r' = 2r), the new force (F') is proportional to 1/(2r)2 = 1/4r2. Therefore, F' = F/4. This shows that when the distance between the charges is doubled, the force becomes one-fourth of its original value.Option A (F/2) is incorrect because it assumes a linear relationship, which does not apply here. Option B (4F) is incorrect as it suggests the force increases with distance, which is contrary to Coulomb's Law. Option C (2F) is incorrect for the same reason as Option A, misinterpreting the inverse-square law of force dependency on distance.
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