If the distance between two point charges is halved, the force between them would be _.
Correct answer: D. Four times
- A. Half
- B. Double
- C. One fourth
- D. Four times
Explanation
The force between two point charges is given by Coulomb's law:F = (kq1q2)/r2where F is the force, q1 and q2 are the charges, r is the distance between them, and k is the Coulomb constant.If the distance between the two charges is halved (i.e., r is divided by 2), then the force between them becomes:F' = (kq1q2)/(r/2)2F' = (kq1q2)/(r2/4)F' = 4xkq1q2)/r2 F' = 4FThus, the force between the two charges is quadrupled (i.e., becomes four times as much) if the distance between them is halved
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