If pKa value of HCN is 3.7 then pKa value of CN is
Correct answer: C. 10.3
- A. 7.3
- B. 3.7
- C. 10.3
- D. 14
Explanation
To find the pKb of CN-, which is the conjugate base of HCN, use the formula: pKa + pKb = 14. Given the pKa of HCN is 3.7, the calculation is: pKb = 14 - 3.7 = 10.3. Therefore, the correct answer is Option C: 10.3. Option A: 7.3 ignores this relationship. Option B: 3.7 mistakenly gives the pKa of HCN instead of the pKb of CN-. Option D: 14 is the sum of pKa and pKb, not the pKb value itself.
Last updated
Related questions
0.1 M HCl has pH = 1.0, it is about 100 times stronger than nitric acid. Then pH of acetic acid will be
1.0 M solution of NaOH is mixed with 1.0 M solution of H₂SO₄+ the solution formed is:
100 ml of each of 0.5 N NaOH, N/5 HCl and N/10 H2SO4 are mixed together. The resulting solution will be:
100 ml of N/5 NaOH will neutralize:
25 ml of a solution of barium hydroxide on titration with a 0.1 molar solution of hydrochloric acid gave a titre value of 35ml. The molarity of barium hydroxide solution was: