If mass attached to a spring and the spring constant of a spring are doubled, the resulting Time period will:
Correct answer: A. Remain Same
- A. Remain Same
- B. Be Doubled
- C. Be Halved
- D. Be Quartered
Explanation
The time period of a spring-mass system is given by:T = 2π√(m/k)where m is the mass and k is the spring constant.If the mass and spring constant are both doubled, then the new time period T' will be:T' = 2π√(2m/2k) = 2π√(m/k) = TTherefore, the time period will remain the same
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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