If magnetic field is given by B= (2i + 3j -8k) and a loop of area 10 sq.m is placed in field in y-z plane, the maximum flux will be:

Explanation

The maximum flux through a loop of area A placed in a magnetic field B is given by the product of the area and the component of the magnetic field perpendicular to the plane of the loop. In this case, the loop is placed in the y-z plane, which is perpendicular to the x-axis. Therefore, the component of the magnetic field perpendicular to the plane of the loop is given by the x-component of the magnetic field, which is 2 Tesla. So, the maximum flux through the loop is given by the product of the area of the loop and the x-component of the magnetic field, which is: Φ = BAcosθ Cos (0°) = 1 Maximum flux ( Φ)= B×A = 2× 10 = 20 Weber. Therefore, the maximum flux through the loop is 20 Weber.