If length of solenoid gets doubled while keeping N (number of turns) constant, the resultant magnetic field will be?
Correct answer: A. B/2
- A. B/2
- B. B/4
- C. 2B
- D. B/3
Explanation
The magnetic field inside a solenoid is given by: B = μ₀ * n * Iwhere:B is the magnetic fieldμ₀ is the permeability of free spacen is the number of turns per unit lengthI is the currentIn this case, the number of turns (N) is constant, and the length (l) is doubled. This means the number of turns per unit length (n = N/l) is halved. Therefore, the magnetic field (B) will also be halved.
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Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
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