If it is projected at an angle of 35o, It hits certain target. It will have the same range if it is projected at an angle of:
Correct answer: C. 55o
- A. 45o
- B. 65°
- C. 55o
- D. 70o
Explanation
Range = (Vi2 sin(2θ))/g Since Vi and g will remain constants in both cases range = sin(2θ) = sin(2x35) = sin(70) = 0.9397 and sin(2 x 55) = sin(110) = 0.9397. Hence, the range for both these will be equal.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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