If frequency of incident light falling on photo emissive plate is doubled. Kinetic energy of emitted photoelectron is:

Correct answer: B. More than double

  • A. Doubled
  • B. More than double
  • C. Unchanged
  • D. Less than double

Explanation

More than double: From Einstein's equation for photoelectric effect , the maximum kinetic energy , K=hν−W where ν= frequency of incident light , h= Planck's constant and W= work function of metal. When ν is made double, K =2hν−W=2(hν−W)+W=2K+W Thus, kinetic energy of photoelectrons will be more than doubled when incident frequency is doubled.

This question appeared on the ETEA MDCAT 2009 paper, which you can sit online with every answer explained.

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About Photons and the Particle Model of Light

The particle model treats light as photons with energy E equals hf and momentum related to wavelength. Questions involve the photoelectric effect, work function, threshold frequency, stopping potential and photon energy, while distinguishing particle behaviour from the wave description of interference and diffraction.

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