If E1 is the energy before the hydraulic jump and E2 is the energy after the hydraulic jump the efficiency of jump is then given by _____________________?
Correct answer: B. E2 / E1
- A. E2 - E1
- B. E2 / E1
- C. E1 - E2
- D. E1 / E2
Explanation
Hydraulic-jump efficiency is the ratio of energy remaining after the jump to energy before it, E2/E1. The difference E1 minus E2 represents the energy loss, not efficiency.
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