If CA is the quantity of reactants initially present, the quantity left after 'n' half periods will be equal to__________________?
Correct answer: B. (½)n CA
- A. (CA/2)n
- B. (½)n CA
- C. (CA/2)1/n
- D. (CA)1/2n
Explanation
Each half-life multiplies the remaining amount by 1/2, so after n half-lives the amount is C_A(1/2)^n. This is option b, whereas (C_A/2)^n incorrectly raises the initial concentration to the nth power.
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