If both temperature and volume of an ideal gas are doubled, the pressure:
Correct answer: A. Remains constant
- A. Remains constant
- B. Increases by a factor of 4
- C. Is also doubled
- D. Is diminished by a factor of 1/4
Explanation
To determine how pressure changes, we use the ideal gas law: PV = nRT. Initially, the pressure is P = nRT/V. If both the temperature (T) and volume (V) are doubled, the new pressure P' = nR(2T)/(2V). Simplifying this results in P' = nRT/V, which is the same as the initial pressure. Hence, the pressure remains constant.Option A is correct because it accurately reflects the result of the calculation. Options B, C, and D are incorrect because they do not account for the equal scaling effect of temperature and volume on pressure, as shown by the ideal gas law.
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Thermal equilibrium means that bodies in contact have the same temperature and no net heat flows between them. The topic distinguishes heat from temperature, uses the zeroth law of thermodynamics, and covers heat transfer, specific heat capacity, thermal expansion and the conditions for reaching equilibrium.
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