If both temperature and volume of an ideal gas are doubled, the pressure:
Correct answer: A. Remains constant
- A. Remains constant
- B. Increases by a factor of 4
- C. Is also doubled
- D. Is diminished by a factor of 1/4
Explanation
To determine how pressure changes, we use the ideal gas law: PV = nRT. Initially, the pressure is P = nRT/V. If both the temperature (T) and volume (V) are doubled, the new pressure P' = nR(2T)/(2V). Simplifying this results in P' = nRT/V, which is the same as the initial pressure. Hence, the pressure remains constant.Option A is correct because it accurately reflects the result of the calculation. Options B, C, and D are incorrect because they do not account for the equal scaling effect of temperature and volume on pressure, as shown by the ideal gas law.
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