If an HCl solution has a concentration of 0.1 M and it requires 30 mL to reach the end point, and during the titration, 15 mL of NaOH solution is used, what is the molarity of the NaOH solution?
Correct answer: B. 0.2 M
- A. 0.1 M
- B. 0.2 M
- C. 0.3 M
- D. 1 M
Explanation
Using the titration formula M1V1=M2V2 for the acid and base. Plugging in the values gives (0.1 M) (30 mL)= Mbase(15 mL). Solving for the molarity of the base yields Mbase= (0.1×30)/15=0.2 M.
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