If an electron in a hydrogen atom jumps from third orbit to the second orbit, the emitted radiation has wavelength (R is the Rydberg's constant):
Correct answer: A. 36 / 5
- A. 36 / 5
- B. 6 / 5R
- C. 5R / 36
- D. 5R / 6
Explanation
For the transition 3 to 2, use the Rydberg formula:1/lambda= R (1/4 - 1/9) = R (5/36) so lambda= 36/5R
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About Atomic Spectra
Atoms emit or absorb light at specific wavelengths because electrons occupy quantized energy levels and change levels by absorbing or releasing photons. The topic covers emission and absorption spectra, spectral series, hydrogen’s line spectrum, energy-level transitions, and the relation between wavelength, frequency and photon energy.
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