if an atom exists in the excited state n=5, the maximum number of transition takes place is
Correct answer: C. 10
- A. 6
- B. 4
- C. 10
- D. 3
Explanation
If an atom is in an excited state with the principal quantum number n = 5, the maximum number of transitions that can take place depends on the number of available lower energy levels. In this case, the atom can transition from the n = 5 level to any of the lower energy levels, i.e., n = 4, 3, 2, or 1.To calculate the maximum number of transitions, we need to consider all possible transitions between these energy levels. The maximum number of transitions can be found using the formula:Maximum number of transitions = (n * (n - 1)) / 2For n = 5:Maximum number of transitions = (5 * (5 - 1)) / 2 = (5 * 4) / 2 = 20 / 2 = 10So, the maximum number of transitions that can take place from the n = 5 excited state is 10
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