If a unit positive charge is placed in air then the flux coming out of it is
Correct answer: D. εo-1
- A. 4 π ε⁰
- B. εo
- C. 4 π/ ε0
- D. εo-1
Explanation
We let a Gaussian surface around the unit positive.According to gausses law Electric flux= Charge enclosed/ εo . In this case the charge enclosed isIs a unit positive charge. So, the Electric field =1/ εo = εo-1
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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