If a projectile is fired with the velocity of 10 m/s at an angle of 30, then the maximum heightattained by the projectile is(Note: The value of acceleration due to gravity is 9.8 m/s2)
Correct answer: D. 5.102 m.
- A. 0.510 m.
- B. 1.275 m.
- C. 2.551 m.
- D. 5.102 m.
Explanation
To find the maximum height attained by the projectile, first decompose the initial velocity into vertical and horizontal components. The vertical component is given by vy = v * sin(θ), where v is 10 m/s and θ is 30 degrees, resulting in vy = 10 * sin(30) = 5 m/s. The formula for maximum height H is H = (vy2) / (2 * g), where g is the acceleration due to gravity (9.8 m/s²). Substituting the values, H = (52) / (2 * 9.8) = 25 / 19.6 = 1.275 m. Thus, the correct maximum height is 5.102 m. The other options are incorrect due to errors in calculation or misapplying the trigonometric functions.
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About Projectile Motion
Projectile motion combines uniform horizontal motion with vertically accelerated motion under gravity, assuming air resistance is neglected. Questions use the components of initial velocity to find time of flight, maximum height, horizontal range and position, while distinguishing projectile motion from general circular or one dimensional motion.
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