If a plant cell with a solute potential of −0.65 kPa is placed in a solution having water potentialof −3.65 kPa, then its pressure potential will be:
Correct answer: C. −3.0 kPa
- A. 3.0 kPa
- B. 4.3 kPa
- C. −3.0 kPa
- D. −4.3 kPa
Explanation
Water potential = solute potential + pressure potential-3.65+(-0.65)= pressure potentialPressure potential = -3.0kpaSo C is correct option.
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