If a dye absorbs a photon of wavelength λ and re-emits the absorbed energy into two photons of wavelengths λ₁ and λ₂ respectively, then:
Correct answer: B. 1/λ = 1/λ₁ + 1/λ₂
- A. λ = λ₁ + λ₂
- B. 1/λ = 1/λ₁ + 1/λ₂
- C. λ = λ₁λ₂ / (λ₁ + λ₂)
- D. λ² = λ₁ ² + λ₂ ²
Explanation
By the law of conservation of energy, the energy of the absorbed photon must equal the sum of the energies of the emitted photons (E = E₁ + E₂) .Since energy is E = hc/λ, this becomes hc/λ = hc/λ₁ + hc/λ₂. Dividing by hc gives the final relationship: 1/λ = 1/λ₁ + 1/λ₂.
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