If a dye absorbs a photon of wavelength λ and re-emits the absorbed energy into two photons of wavelengths λ₁ and λ₂ respectively, then:
Correct answer: B. 1/λ = 1/λ₁ + 1/λ₂
- A. λ = λ₁ + λ₂
- B. 1/λ = 1/λ₁ + 1/λ₂
- C. λ = λ₁λ₂ / (λ₁ + λ₂)
- D. λ² = λ₁ ² + λ₂ ²
Explanation
By the law of conservation of energy, the energy of the absorbed photon must equal the sum of the energies of the emitted photons (E = E₁ + E₂) .Since energy is E = hc/λ, this becomes hc/λ = hc/λ₁ + hc/λ₂. Dividing by hc gives the final relationship: 1/λ = 1/λ₁ + 1/λ₂.
Last updated
About Atomic Structure
Atomic structure covers the discovery of the proton, Planck's quantum theory, hydrogen emission spectra and the evidence for quantized energy levels. You will use quantum numbers to describe orbitals, distinguish s, p, d and f orbital shapes, and write electronic configurations, including the correct order of electron filling.
Practise Atomic Structure
922 free Atomic Structure MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemistry questions like this
Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
168 O-2 has how many electrons in s-orbitals?
3s2, 3p4 valence shell electronic configuration corresponds to ?
6Y = 2s12P1x2P1y2P1z this is_configuration
A 1-kW radio frequency of 880 KHz. How many quantas per second does it emit?
A 1kW radio transmitter operates at a frequency of 880 kHz. How many quanta per second does it emit?