If a dihybrid cross is made between Pisum sativum plants having Yellow/Round and Green/Wrinkled seeds. Which of the following results are not shown in the F2 generation?
Correct answer: A. Yellow/Round- 3/16
- A. Yellow/Round- 3/16
- B. Yellow/Wrinkled-3/16
- C. Green/Round-3/16
- D. Green/Wrinkled 1/16
Explanation
In a dihybrid cross between Pisum sativum plants with Yellow/Round seeds (YyRr) and Green/Wrinkled seeds (yyrr), the F2 generation will display a phenotypic ratio of 9:3:3:1. This means the offspring will segregate as follows:9 will have Yellow/Round seeds.3 will have Yellow/Wrinkled seeds.3 will have Green/Round seeds.1 will have Green/Wrinkled seeds.This ratio follows Mendel's law of independent assortment, where the genes for seed color and seed shape assort independently during gamete formation.
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Mendel's laws explain segregation, independent assortment and the prediction of genetic ratios using alleles, genotypes and phenotypes. The chapter also covers linked genes, recombination and crossing over during meiosis, then applies pedigree reasoning to X-linked recessive traits, which show different inheritance patterns in males and females.
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