If a cylinder has 640 cm³ of gas in it at 0℃, how many parts of its volume increase or decrease by 1℃ rise or fall in temperature?
Correct answer: A. 2.3 cm³
- A. 2.3 cm³
- B. 4 cm³
- C. 2 cm³
- D. 3.4 cm³
Explanation
According to Charles' law: V1 / T1 = V2 / T2 Where V = volume and T = temperature in Kelvins 1°C change in temperature = 1 K change 640 / 273 = x / (273 + 1) x = 640 x 274 / 273 ≈ 642.3 642.3 - 640 = 2.3 cm^3
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About Charles's Law
At constant pressure, the volume of a fixed mass of gas is directly proportional to its absolute temperature. Questions involve the Kelvin scale, the equation V₁/T₁ = V₂/T₂, volume-temperature graphs, and the need to distinguish Charles's law from Boyle's law, which relates pressure and volume.
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