If a cylinder has 640 cm³ of gas in it at 0℃, how many parts of its volume increase or decrease by 1℃ rise or fall in temperature?
Correct answer: A. 2.3 cm³
- A. 2.3 cm³
- B. 4 cm³
- C. 2 cm³
- D. 3.4 cm³
Explanation
According to Charles' law: V1 / T1 = V2 / T2 Where V = volume and T = temperature in Kelvins 1°C change in temperature = 1 K change 640 / 273 = x / (273 + 1) x = 640 x 274 / 273 ≈ 642.3 642.3 - 640 = 2.3 cm^3
Last updated
About Charles's Law
At constant pressure, the volume of a fixed mass of gas is directly proportional to its absolute temperature. Questions involve the Kelvin scale, the equation V₁/T₁ = V₂/T₂, volume-temperature graphs, and the need to distinguish Charles's law from Boyle's law, which relates pressure and volume.
Practise Gases
443 free Gases MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemistry questions like this
Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
A certain volume of a gas at zero degree Celsius temperature and 1 atm pressure is 0.5 L. If the temperature is raised to 300 degrees Celsius by keeping the pressure constant, then what will be its final volume?
A child's balloon has a volume 3.80 dm3, when the temperature is 35°C. If the balloon is put in a refrigerator and cooled to 5°C, the approximate volume of the balloon is (assume pressure inside the balloon is equal to atmospheric pressure):
A gas at 27 degrees C is heated at constant pressure until its volume doubles. Its final temperature is
A gas occupies 300 cm3 at 27 degrees Celsius. At constant pressure, what volume will it occupy at 127 degrees Celsius?
At constant pressure, the graph between V and T is: