If a 3.5 F capacitor has a potential difference of 9 V across it, then the charge on the capacitor will be
Correct answer: D. 31.5 C.
- A. 2.5 C.
- B. 5.5 C.
- C. 12.5 C.
- D. 31.5 C.
Explanation
The relationship between charge (Q), capacitance (C), and potential difference (V) across a capacitor is given by the formula:Q = C × VWhere: * Q = Charge in Coulombs (C) * C = Capacitance in Farads (F) * V = Potential difference in Volts (V)Given values from the question: * Capacitance (C) = 3.5 F * Potential difference (V) = 9 VSubstitute these values into the formula:Q = 3.5 F × 9 VQ = 31.5 CTherefore, the charge on the capacitor is 31.5 C.
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About Capacitors
Capacitors store electric charge and energy in an electric field between conductors. Work includes capacitance, the relation Q = CV, dielectric materials, charging and discharging, energy formulas, and combinations of capacitors in series and parallel. Electric potential difference is needed to understand why charge and stored energy change.
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