If a 2µF capacitor has a charge of 20µC, the potential difference between the plates is:
Correct answer: A. 10V
- A. 10V
- B. 20V
- C. 40V
- D. 50V
Explanation
Explanation is given below:V=Q/C= 20 x 10 -6/ 2 x 10-6= 10 V
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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