If 50 KV is the applied potential in ax X-ray tube then the minimum wavelength of X-rays produced is:
Correct answer: C. 0.02 nm
- A. 0.2 nm
- B. 2 nm
- C. 0.02 nm
- D. 2 Å
Explanation
To find the minimum wavelength of X-rays produced in an X-ray tube, we use the formula: 𝝺min = hc/qeV, where:h is Planck's constant (6.626 x 10-34 Js)c is the speed of light (3 x 108 m/s)q is the charge of an electron (1.6 x 10-19 C)V is the applied voltage (50 x 103 V)Plugging in these values, we get:𝝺min = (6.626 x 10-34 Js * 3 x 108 m/s) / (1.6 x 10-19 C * 50 x 103 V) = 0.0248 nm, which rounds to 0.02 nm.The other options are incorrect because they result from incorrect calculations or unit conversions.
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