If 50 KV is the applied potential in ax X-ray tube then the minimum wavelength of X-rays produced is:
Correct answer: C. 0.02 nm
- A. 0.2 nm
- B. 2 nm
- C. 0.02 nm
- D. 2 Å
Explanation
To find the minimum wavelength of X-rays produced in an X-ray tube, we use the formula: 𝝺min = hc/qeV, where:h is Planck's constant (6.626 x 10-34 Js)c is the speed of light (3 x 108 m/s)q is the charge of an electron (1.6 x 10-19 C)V is the applied voltage (50 x 103 V)Plugging in these values, we get:𝝺min = (6.626 x 10-34 Js * 3 x 108 m/s) / (1.6 x 10-19 C * 50 x 103 V) = 0.0248 nm, which rounds to 0.02 nm.The other options are incorrect because they result from incorrect calculations or unit conversions.
This question appeared on the ETEA MDCAT 2016 paper, which you can sit online with every answer explained.
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