If 41 gram of H2SO4 react with 80 gram of NaOH how much reactant will be left over after the reaction is complete
Correct answer: C. 46.5g NaOH
- A. 24.5g H2SO4
- B. 20g NaOH
- C. 46.5g NaOH
- D. 60g NaOH
Explanation
Mr of NaOH= 23 + 16 + 1 = 40g/molMr of H2SO4= (2x1) + 32 + (4x16) = 98g/mol2NaOH + H2SO4 => Na2SO4 +2H2O2x40g. 98g. xg. 41gx= 33.5g80-33.5 => 46.5g of NaOH
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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