If 41 gram of H2SO4 react with 80 gram of NaOH how much reactant will be left over after the reaction is complete
Correct answer: C. 46.5g NaOH
- A. 24.5g H2SO4
- B. 13.5g NaOH
- C. 46.5g NaOH
- D. 60g NaOH
Explanation
Mr of NaOH= 23 + 16 + 1 = 40g/molMr of H2SO4= (2x1) + 32 + (4x16) = 98g/mol2NaOH + H2SO4 => Na2SO4 +2H2O2x40g. 98g. xg. 41gx= 33.5g80-33.5 => 46.5g of NaOH.
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