if 20 g CaCO3 is a added to 20 gram HCl select the true statement.
Correct answer: A. CaCO3 is limiting reagent
- A. CaCO3 is limiting reagent
- B. Both are consumed completely
- C. HCL is limiting reagent
- D. There is no reaction
Explanation
the equation for the reaction is CaCO3 + 2HCl → CO2 + H2O + CaCl2 Mr of HCl= 1 + 35.5 = 36.5 Mr of CaCO3= 40 + 12 + (3x16) = 100 2x36.5g of HCl => 1 mole of CaCl2 20g of HCl => x mole of CaCl2 x= 0.27mol 100g of CaCO3 => 1 mole of CaCl2 20g of CaCO3 => x mole of CaCl2 x= 0.2mol As lesser moles of CaCl2 (product) is produced by CaCO3 hence it is the limiting reactant.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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