If 2% of the main current is to be passed through a galvanometer of resistance G, then resistance of the shunt required is ________________?
Correct answer: B. G/49
- A. G/50
- B. G/49
- C. 49 G
- D. 50 G
Explanation
If 2% flows through the galvanometer, 98% flows through the shunt, so the shunt current is 49 times the galvanometer current. Since parallel branches have equal voltage, G I_g = R_s(49 I_g), giving R_s = G/49.
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