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If 1.002 x 10^6 J of thermal energy is required to melt some ice at its melting point, what is the mass of ice that melts? (Specific latent heat of fusion of ice is 334 J/g)

Correct answer: C. 3 kg

  • A. 1 kg
  • B. 2 kg
  • C. 3 kg
  • D. 4 kg

Explanation

Q = mLwhere Q is the amount of thermal energy required to melt the ice, m is the mass of ice, and L is the specific latent heat of fusion of ice.Substituting the given values, we get:1.002 x 106 J = m x 334 J/gSolving for m, we get:m = (1.002 x 106 J) / (334 J/g) = 2997.60 g m= 3000 g = 3 kg Mathematically the other options are incorrect.

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