If 1.002 x 10^6 J of thermal energy is required to melt some ice at its melting point, what is the mass of ice that melts? (Specific latent heat of fusion of ice is 334 J/g)
Correct answer: C. 3 kg
- A. 1 kg
- B. 2 kg
- C. 3 kg
- D. 4 kg
Explanation
Q = mLwhere Q is the amount of thermal energy required to melt the ice, m is the mass of ice, and L is the specific latent heat of fusion of ice.Substituting the given values, we get:1.002 x 106 J = m x 334 J/gSolving for m, we get:m = (1.002 x 106 J) / (334 J/g) = 2997.60 g m= 3000 g = 3 kg Mathematically the other options are incorrect.
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Thermal equilibrium means that bodies in contact have the same temperature and no net heat flows between them. The topic distinguishes heat from temperature, uses the zeroth law of thermodynamics, and covers heat transfer, specific heat capacity, thermal expansion and the conditions for reaching equilibrium.
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