Asked in PMC Practice Test 7 (2021) 2021Moderate

Identify the de Broglie expression from the following.

Correct answer: B. λ=h/p

  • A. λ= hxp
  • B. λ=h/p
  • C. λ=h+p
  • D. λ=h-p

Explanation

λ= h/p This equation relating the momentum of a particle with its wavelength is de Broglie equation and the wavelength calculated using this relation is de Broglie wavelength The wave properties of matter are only observable for very small objects, de Broglie wavelength of a double-slit interference pattern is produced by using electrons as the source. 10 eV electrons (which is the typical energy of an electron in an electron microscope): de Broglie wavelength = 3.9 x 10-10 m. Option A,C and D are incorrect

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About Quantum Theory and Radiation

Quantum theory treats electromagnetic radiation as packets of energy called photons, with energy proportional to frequency through E equals hf. The topic covers Planck's hypothesis, photon momentum, the photoelectric effect, threshold frequency, work function and wave particle duality, distinguishing quantised energy exchange from classical continuous radiation.

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