Identify the correct option with the same empirical formula for both compounds:
Correct answer: D. C6H12O6 & CH3COOH
- A. H2O & H2O2
- B. C6H12 & C6H6
- C. H2S2O3 & H2SO4
- D. C6H12O6 & CH3COOH
Explanation
The Empirical formula is the formula, giving us the proportions of elements present in a compound. To find that, all numbers of atoms in a compound have to be divided by a common number. Only option D gives the same empirical formula for both compounds. Dividing the number of atoms in C6H12O6 by 6 and CH3COOH by 2, both of them give C2O as the answer. For ease, CH3COOH can be first written as C2H4O2 and then divided by 2.Other options are wrong as they have compounds with different empirical formulae with; A having H2O & HO,B having CH2 & CH,C having H2S2O3 & H2SO4.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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