IC = [a / (1 - a )] IB + [___________ / (1 - a )?
Correct answer: A. ICBO
- A. ICBO
- B. ICEO
- C. IC
- D. IE
Explanation
Using α = IC/IE and IE = IB + IC, the common-base relation becomes IC = [α/(1 − α)]IB + ICBO/(1 − α). Therefore the missing term is ICBO.
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