Hybridization of 1 and 2 carbon atom in CH2=C=CH2:

Explanation

In the molecule CH2=C=CH2, the first and third carbon atoms (CH2 groups) are sp2 hybridized because they each form a double bond with the central carbon, allowing for a trigonal planar geometry. The central carbon atom is sp hybridized as it forms two double bonds, providing a linear geometry. This hybridization allows for the linear arrangement of the central carbon's orbitals, accommodating the double bonds on both sides. Option C is correct because it accurately reflects the hybridization states of the carbon atoms in the molecule. Other options incorrectly describe the hybridization states, either by mismatching the type or the geometry required for the described bonds.