How much will be the length of a simple pendulum if its period is one second?
Correct answer: B. 0.25 m
- A. 2.5 m
- B. 0.25 m
- C. 25 m
- D. 0.025 m
Explanation
The length of a simple pendulum can be calculated using the formula:L = gT² / 4π²Where 'L' is the length of the pendulum, 'g' is the acceleration due to gravity (approximately 9.8 m/s²), and 'T' is the period of the pendulum. Given that the period (T) is one second. Putting the values in the above equation, we get:L = 9.8 × (1)² / 4π²L = 0.248 mL ≈ 0.25 m
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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