How much energy is required to raise the temperature of 5.00 kg of lead from 20.0•c to its melting point of 327°C? The specific heat of lead is 128 J/kg ?•c.
Correct answer: A. 1.96 x 10^5 J
- A. 1.96 x 10^5 J
- B. 4.04 X 10^5 J
- C. 1.07 X 10^5 J
- D. 8.15 x 10^4 J
Explanation
According to formula of Specific Heat Capacity ( c ), c = Q / m T Rearranging for Heat Energy ( Q ), Q = c m T Q = 128 x 5 x ( 327-20 ) Q = 1.96 x 105 J
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Thermal equilibrium means that bodies in contact have the same temperature and no net heat flows between them. The topic distinguishes heat from temperature, uses the zeroth law of thermodynamics, and covers heat transfer, specific heat capacity, thermal expansion and the conditions for reaching equilibrium.
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