How much energy is converted in a resistor of 5 ohm carrying a current of 2.0 A after 10 seconds?
Correct answer: D. 200 J
- A. 4.0 J
- B. 25 J
- C. 100 J
- D. 200 J
Explanation
Explanation:The energy (E) dissipated in a resistor is given by the formula: E = I²Rt, where I is the current, R is the resistance, and t is the time.Substituting the given values: E = (2.0 A)² * (5 Ω) * (10 s) = 4 * 5 * 10 = 200 J.
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