How many moles of helium gas occupy 22.41 at 0°C at 1 atm. Pressure
Correct answer: C. 1.0
- A. 011
- B. 0.90
- C. 1.0
- D. 1.11
Explanation
To find the number of moles of a gas, you can use the ideal gas law equation:PV=nRTWhere:● P is the pressure of the gas (in atm),● V is the volume of the gas (in liters),● n is the number of moles of the gas,● R is the ideal gas constant (0.0821 L⋅atm/mol⋅K0.0821L⋅atm/mol⋅K),● T is the temperature of the gas (in Kelvin).Given:● P=1atm (pressure),● V=22.41L (volume),● T=0∘C (temperature).Convert the temperature to Kelvin: TK=T∘C+273.15TK =0+273.15TK =273.15KNow, substitute these values into the ideal gas law equation:(1 atm)⋅(22.41 L)=n⋅(0.0821 L⋅atm/mol⋅K)⋅(273.15 K)Solve for n (number of moles):22.41=n⋅22.4145n≈22.41/4522.41 n≈0.999So, the number of moles (n) of helium gas is approximately 0.999.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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