How many grams of calcium oxide are produced when 1 mole of calcium carbonate decomposes completely, given CaCO3 gives CaO + CO2?
Correct answer: D. 56 g
- A. 100 g
- B. 44 g
- C. 40 g
- D. 56 g
Explanation
The equation shows a one to one ratio, so 1 mole of CaCO3 gives 1 mole of CaO, whose molar mass is 40 + 16, that is 56 g. The value 100 g is the molar mass of the calcium carbonate that decomposed and 44 g is the mass of carbon dioxide released, and note that 56 plus 44 equals 100, which confirms mass is conserved.
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About Theoretical and Percentage Yield
Theoretical yield is the maximum product predicted from a balanced equation and the amount of limiting reactant. Work includes identifying the limiting reagent, comparing theoretical and actual yield, and calculating percentage yield using stoichiometric mole relationships.
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