Heat transfer co-efficient, hG(Kcal/hr.m2 .°C) and mass velocity of air, G (kg/hr.m2 ) for air flow parallel to the surface in case of constant drying rate in batch drying is related as hG = 0.0176G0.8. But when the flow of air perpendicular to the surface is encountered, this equation changes to ____________________?

Correct answer: A. hG = 1.004G0.37

  • A. hG = 1.004G0.37
  • B. 1.004G0.8
  • C. hG = 0.0176G0.37
  • D. 0.0176G1.37

Explanation

For air flowing perpendicular to the drying surface, the empirical correlation changes to hG = 1.004G^0.37. The exponent and coefficient differ from the parallel-flow relation because the flow pattern changes the boundary layer.

Written and checked by , MS Computer ScienceLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? support@testustad.com

Practise Heat Transfer Operations

645 free Heat Transfer Operations MCQs from Chemical Engineering, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Exams that ask Chemical Engineering questions like this

Chemical Engineering is on this paper prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for it.

More Heat Transfer Operations questions